c - Convert pointer address to char array and make it little-endian -

in c, if have a:

char *ptr; 

and if, let's say, ptr points address 0xbfc70753, how can convert array of char end array of char addr contain:

char addr[4] = "\x53\x07\xc7\xbf" 

that is, convert address pointed @ ptr array of char , make little-endian.

(kali linux, 32 bit, intel)

if on little-endian machine, nice way it:

void foo(uint32_t* adr, uint32_t value){*adr = value;}   int main(int argc, char** argc) {     char *ptr = ...     char adr[4];      foo((uint32_t*)adr,(uint32_t)ptr); } 

the idea 32-bit unsigned integers in little-endian, when copy them char array, each byte goes place want.