regex - java.lang.IndexOutOfBoundsException: No group 1 | Pattern matching -


i trying extract value of version accept header can of form

"vnd.example-com.foo+json; version=1.1"

here code extracting version

val resourceversionpattern: pattern = pattern.compile("(?<=version=).*")  def getresourceversion(acceptheader: string): string = {             import java.util.regex.matcher             val matcher: matcher = resourceversionpattern.matcher(acceptheader)             if(matcher.find()) ("v" + matcher.group(1)).trim() else "v1.0"     }

when invoking above function intended extract version (for example can of form v1.0 or v1.5 or v2.5) 

 getresourceversion("vnd.example-com.foo+json; version=1.1")

i following exception:

java.lang.indexoutofboundsexception: no group 1 @ java.util.regex.matcher.group(matcher.java:487) @ .getresourceversion(<console>:12) @ .<init>(<console>:11) @ .<clinit>(<console>) @ .<init>(<console>:11) @ .<clinit>(<console>) @ $print(<console>) @ sun.reflect.nativemethodaccessorimpl.invoke0(native method) @ sun.reflect.nativemethodaccessorimpl.invoke(nativemethodaccessorimpl.java:57) @    sun.reflect.delegatingmethodaccessorimpl.invoke(delegatingmethodaccessorimpl.java:43) @ java.lang.reflect.method.invoke(method.java:606) @ scala.tools.nsc.interpreter.imain$readevalprint.call(imain.scala:704) @ scala.tools.nsc.interpreter.imain$request$$anonfun$14.apply(imain.scala:920) @ scala.tools.nsc.interpreter.line$$anonfun$1.apply$mcv$sp(line.scala:43) @ scala.tools.nsc.io.package$$anon$2.run(package.scala:25) @ java.lang.thread.run(thread.java:744)

i think doing wrong in regex or input string has illegal charecters not able identify limited knowledge of regular expression. me find out reason.

it'd advise against (ab)using look-behind, if possible write 1 without clear , same thing.

just use pattern:

version=(.*)

and want in capturing group 1.


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