Python - Generate binary list with itertools -


i want generate following output:

[11000] combinations these numbers, no doubles

   [11000]    [01100]    [00110]    [00011]    [10100]    .    .    .

but cannot figure out how that. in problem list has 365 values 20 ones.

you have 365 possible positions place 20 ones. 1 way approach making 20-length combinations of 365 positions.

an example of how in code:

from itertools import combinations  n = 365 r = 20  indexes in combinations(range(n), r):     base = [0]*n     in indexes:         base[i] = 1     print(base)

since "n choose r" problem, you'll have lots of possible combinations! calculate how many, use: n! / (r!(n-r)!) = 365! / (20!(365-20)!) = 426112827338828179808453831565930.


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