java - Short|quick int values comparison -


i learned terminary expression, want little different.

i have following:

int mode = getmyintvalue();

i comparison following:

if(mode == 1 || mode == 2 || mode == 3) //do

i know if there short way of doing this, tried didn't work:

if(mode == 1 || 2 || 3) //do

there short|quick way of doing it? quick "ifs" because makes code more clear, example, more clear this:

system.out.println(mode == 1 ? text1 : text2):

than this:

if(mode == 1) system.out.println(text1):  else system.out.println(text1):

thanks in advance!

well, if don't mind boxing hit, use set prepared earlier:

// use more appropriate name if necessary private static final set<integer> valid_modes     = new hashset<>(arrays.aslist(1, 2, 3));  ...  if (valid_modes.contains(mode)) { }

you use int[] , custom "does array contain value" method if wanted... o(n) or o(log n) binary search, suspect we're talking small sets anyway.


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