Submit Form and return values using HTML / JQuery / PHP -


need ... homepage have 3 divs, #header, #content, #footer. other pages being opened inside #content div. in 1 of pages have form 2 select lists , 1 submit button. want click button , return page #content div, showing values select before. this:

the origin is: 1
destiny is: 1

but code returns following ...

notice: undefined variable: origin in ... notice: undefined variable: destiny in ...

note: working if don't open page inside #content div

my html:

<form id="myform" name="myform" action="values.php" method="post">     <select id="origin" name="origin">         <option value="0" selected>-- select origin --</option>         <option value="1">portugal</option></select>     <select id="destiny" name="destiny">         <option value="0" selected>-- select destiny --</option>         <option value="1">lisboa</option></select>     <input id="btsubmit" name="btsubmit" type="submit" value="search!"> </form>

my function:

$(document).ready(function(){     $('#btsubmit').click(function(e) {         e.preventdefault();         var url = $('#myform').attr('action');         var method = $('#myform').attr('method');     $.ajax({         type: method,         url: url,         data: $('#myform').serialize(),         success: $('#content').load(url)         });     }); });

my values.php page:

<?php     if(isset($_post['origin']) || isset($_post['destiny']))      {         $origin = $_post['origin'];         $destiny = $_post['destiny'];     }     echo 'the origin is:' . $origin . '<br>';     echo 'the destiny is:' . $destiny; ?>

you should not call load again - have called $.ajax , received results. need display them in content:

success: function (data) {     $('#content').html(data); }

-

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